Python Read Large File. The iterator will return each line one by one, which can be processed. Break for line in lines:
Read File in Python Python Electroica Blog
Web the best solution i found regarding this, and i tried it on 330 mb file. #do something #i in line of that line #row containts all data of that line. The iterator will return each line one by one, which can be processed. With open (file_name, ru) as read_file: Process(line) or, for line in file(datafile): Lineno = 500 line_length = 8 with open ('catfour.txt', 'r') as file: Essentially, i'm looking for a more efficient way of doing: For i, row in enumerate (read_file, 1): Open (filename).read () [start_index:end_index] python parsing share improve this question follow asked mar 26, 2013 at 18:36 cerin In other words, does the processing take more time than the reading?
Web 1 with a file of that size, i believe the more important question is what are you doing with the data as you read it? instead of how to read it. Web the best solution i found regarding this, and i tried it on 330 mb file. This will not read the whole file into memory and it’s suitable to read large files in python. In other words, does the processing take more time than the reading? Process(line) or, for line in file(datafile): With open (file_name, ru) as read_file: To read large text files in python, we can use the file object as an iterator to iterate over the file and perform the required task. Web i'm using python 2.6.2 [gcc 4.3.3] running on ubuntu 9.04. Lineno = 500 line_length = 8 with open ('catfour.txt', 'r') as file: #do something #i in line of that line #row containts all data of that line. Web 1 with a file of that size, i believe the more important question is what are you doing with the data as you read it? instead of how to read it.
